New and old UPS battery replacement method

Label: The replacement of UPS battery packs uses the reverse blocking characteristics of diodes to artificially make a voltage difference between the new and old battery packs (GB, GB'). When the new battery GB' is put in and the old battery pack GB is withdrawn, the diode is used As an electronic switch, it supplies power to the DC bus instantaneously, thereby avoiding the circulation of the new and old battery packs during the parallel connection process due to the difference in voltage, and ensuring the stability of the DC power supply. At the same time, it also avoids the factors that may cause unreliability of the DC system due to interruption of the DC bus power supply box and no battery pack power supply during the replacement of the UPS battery pack. The method is: 1. Stop the operation of charger 2#U, and remove the fuse FU connected in series in the UPS battery pack GB'. 2. Connect the diode V (2CZ200A/800V) in parallel at points A and C at both ends of the fuse FU5. 3. After checking the wiring, send it to the battery fuse FU. 4. Remove the fuse FU5, connect the diode V to the circuit, and connect to SA3. Check that the cathode pair of the diode—WOM voltage is about 241V, the anode pair—WOM voltage is about 218V, and the diode is reversely cut off. The DC bus is powered by charger 1#U, battery pack GB, GB’ in parallel, but because the battery pack GB’s voltage is low, the DC load is powered by charger 1#U, battery pack GB. 5. Disconnect SA1 and remove the fuses FU3 and FU4. The battery pack GB' instantaneously supplies power to the DC bus through the diode V. 6. Start the charger 2#U and adjust its voltage to the rated value. The DC bus is powered by the charger 2#U and the storage battery GB' in parallel. 7. Remove the old battery pack GB from the battery screen, and connect its positive and negative leads to the positive and negative poles of charger 1#U respectively at the nearby DC screen connection number. 8. Start the charger 1#U and make it parallel to the assembled old battery and the voltage is 241V. 9. The charger 2#U is disabled, and the voltage of the battery pack GB’ drops to about 235V for a short time. 10. Combine SA1, charger 1#U, the old battery pack GB, and the new battery pack GB' are connected in parallel to supply power to the DC bus, but because the voltage of the charger 1#U in parallel with the old battery pack GB is higher than that of the new battery pack GB' Therefore, the load current is supplied by the charger 1#U and the old battery pack GB, but because the diode V is reversely cut off, the new battery pack GB' will not be reverse-charged. 11. Disconnect SA3, remove the new battery pack GB' and install it on the battery screen. 12. Connect the diode V parallel to both ends of the fuse FU5 to both ends of the fuse FU3. 13. Install fuse FU4, charger 1#U, the new and old battery packs are connected in parallel to supply power to the DC bus. Due to the diode V, charger 1#U, the old battery pack only supplies power to the DC bus, not the new battery pack. Recharge. 14. Disconnect SA1, and the new UPS battery pack supplies power to the DC bus through the diode V. 15. Install the fuse FU3, and the diode V is short-circuited. At this time, the diode V has lost its function and should be removed with power. 16. Remove the old battery pack. 17. Combine SA1, charger 1#U and the new battery pack in parallel to supply power to the DC bus.
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